7[2-(3+2x)]=-9+2(1-8x)

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Solution for 7[2-(3+2x)]=-9+2(1-8x) equation:


Simplifying
7[2 + -1(3 + 2x)] = -9 + 2(1 + -8x)
7[2 + (3 * -1 + 2x * -1)] = -9 + 2(1 + -8x)
7[2 + (-3 + -2x)] = -9 + 2(1 + -8x)

Combine like terms: 2 + -3 = -1
7[-1 + -2x] = -9 + 2(1 + -8x)
[-1 * 7 + -2x * 7] = -9 + 2(1 + -8x)
[-7 + -14x] = -9 + 2(1 + -8x)
-7 + -14x = -9 + (1 * 2 + -8x * 2)
-7 + -14x = -9 + (2 + -16x)

Combine like terms: -9 + 2 = -7
-7 + -14x = -7 + -16x

Add '7' to each side of the equation.
-7 + 7 + -14x = -7 + 7 + -16x

Combine like terms: -7 + 7 = 0
0 + -14x = -7 + 7 + -16x
-14x = -7 + 7 + -16x

Combine like terms: -7 + 7 = 0
-14x = 0 + -16x
-14x = -16x

Solving
-14x = -16x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '16x' to each side of the equation.
-14x + 16x = -16x + 16x

Combine like terms: -14x + 16x = 2x
2x = -16x + 16x

Combine like terms: -16x + 16x = 0
2x = 0

Divide each side by '2'.
x = 0

Simplifying
x = 0

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